18x^2-51x+25=0

Solution for 18x^2-51x+25=0 equation:

18x^2-51x+25=0

a = 18; b = -51; c = +25;
Δ = b2-4ac
Δ = -512-4·18·25
Δ = 801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{801}=\sqrt{9*89}=\sqrt{9}*\sqrt{89}=3\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-3\sqrt{89}}{2*18}=\frac{51-3\sqrt{89}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+3\sqrt{89}}{2*18}=\frac{51+3\sqrt{89}}{36}
$